You have 2 boxes that contains 100 balls each, and the balls can be white, blue, red, or half red and blue.
Box A contains:
- 90 white balls
- 10 red balls
Box B contains:
- 86 white balls
- 4 red balls
- 9 blue balls
- 1 red and blue ball
If you don't know which box you pick a ball from (the probability is equal for what box you chose), what is the probability for pulling exactly 2 white balls and 1 red ball, if you don't put it back and don't take a look at the balls until all 3 are pulled from the box you chose? (You only pick 3 balls).
I thought this would be pretty straight forward by using combinatorics:
P(1 red and 2 white balls) = $\frac{176 \choose 2}{200 \choose 3}$$14\choose 1$
But this gives me the wrong answer.
Please help me solve this problem, any suggestions would be appreciated.