Timeline for How to compute the partial fraction decomposition of $\frac{6}{x^4(x+1)}$?
Current License: CC BY-SA 4.0
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| when toggle format | what | by | license | comment | |
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| Apr 28 at 4:54 | answer | added | ultralegend5385 | timeline score: 3 | |
| Apr 27 at 23:31 | answer | added | Frank W | timeline score: 2 | |
| Apr 27 at 23:16 | history | edited | Thomas Andrews | CC BY-SA 4.0 |
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| Apr 27 at 23:00 | comment | added | J.G. | Hi, welcome to Math SE. Hint: since $\frac{1}{x(x+1)}=\frac1x-\frac{1}{x+1}$,$$\frac{1}{x^2(x+1)}=\frac{1}{x^2}-\frac{1}{x(x+1)}=\frac{1}{x^2}-\frac1x+\frac{1}{x+1}.$$Now repeat. | |
| Apr 27 at 22:31 | answer | added | heropup | timeline score: 6 | |
| Apr 27 at 22:30 | comment | added | Greg Martin | What examples have you done before where there are linear factors with multiplicity in the denominator? | |
| S Apr 27 at 22:23 | review | First questions | |||
| Apr 27 at 22:33 | |||||
| S Apr 27 at 22:23 | history | asked | Iris Gu | CC BY-SA 4.0 |