Question
Question: In the figure, A
0
A
1
,A
2
A
3
,A
4
A
5
$A_0A_1,A_2A_3,A_4A_3...$ ,… areare all perpendicular to L 1 ;A 1 A 2 ,A 3 A 4 ,A 5 A$L_1$
6$A_1A_2,A_3A_4,A_5A_6...$ ,… are all perpendicular to L 2 . If A 0 A 1 =1 and A 0 A 1 +A 1 A 2 +A 2 A 3 +…∞=2(2+ √3 ), find θ.$L_2$
iIf $A_0A_1=1$
And $A_0A_1+A_1A_2+A_2A_3+A_3A_4......\infty =2(2+ \sqrt3)$
Find $\theta$
I figured that all the triangles formed are similar and hence the cosθ$\cos θ$ is constant. now
Now for finding the sum AoA1=A1A2=... =cosθ, $A_0A_1=A_1A_2=... =\ cos θ$
S = cosθ+cosθ+cosθ+....(infinite times) = 2(2+ √3)$S = \cos θ+\cos θ+\cos θ+....\mathrm{(infinite\ times)} = 2(2+ √3)$
how can iI determine theta$\theta$?
