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Mar 22, 2023 at 8:41 comment added Elías Guisado Villalgordo @VladimirSotirov I just edited the phrasing in the first sentence. Thank you so much for the new comment in the other post detailing your argument ^^
Mar 22, 2023 at 8:38 history edited Elías Guisado Villalgordo CC BY-SA 4.0
changed phrasing
Mar 21, 2023 at 19:11 comment added Vladimir Sotirov I did not suggest that every ring homomorphism between $\mathbb R$-algebras is $\mathbb R$-linear. I only claimed it for $1$-dimensional $\mathbb R$-algberas (i.e. between rings of real numbers). The consequence of that was that the components of morphisms of certain locally ringed spaces (those arising from real algebras of smooth functions) are automatically real-linear if they are ring homomorphisms. The argument crucially used that those homomorphisms are components of a morphism between those locally ringed spaces.
Mar 21, 2023 at 13:54 vote accept Elías Guisado Villalgordo
Mar 21, 2023 at 12:41 history undeleted Elías Guisado Villalgordo
Mar 21, 2023 at 12:25 history deleted Elías Guisado Villalgordo via Vote
Mar 21, 2023 at 12:25 answer added Captain Lama timeline score: 1
Mar 21, 2023 at 12:15 history asked Elías Guisado Villalgordo CC BY-SA 4.0