Timeline for Integral of $\log(1-x^t)$ with respect to $t$
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
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| S Jun 15, 2023 at 0:35 | history | suggested | Starship | CC BY-SA 4.0 |
removed "Thanks in Advantage"
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| Jun 15, 2023 at 0:18 | review | Suggested edits | |||
| S Jun 15, 2023 at 0:35 | |||||
| Sep 9, 2018 at 1:57 | audit | Reopen votes | |||
| Sep 9, 2018 at 11:16 | |||||
| Sep 1, 2018 at 18:29 | audit | Close votes | |||
| Sep 1, 2018 at 18:29 | |||||
| Aug 23, 2018 at 11:14 | audit | Close votes | |||
| Aug 23, 2018 at 11:14 | |||||
| Aug 13, 2018 at 12:00 | vote | accept | user3141592 | ||
| Aug 13, 2018 at 2:06 | answer | added | Szeto | timeline score: 6 | |
| Aug 13, 2018 at 1:04 | comment | added | Mathew | sorry, t=1/2 was a bad example, here is another, take t=5/2, this still gives the same problem if complex numbers appearing in the integrand | |
| S Aug 13, 2018 at 0:51 | history | suggested | Mathew | CC BY-SA 4.0 |
the question title is inconsistent with the question in that n was used in the title but t was used in the question, I fixed this
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| Aug 13, 2018 at 0:48 | comment | added | user3141592 | @mathew Regarding the limits of integrations, $t \ge 2$ | |
| Aug 13, 2018 at 0:45 | comment | added | Mathew | unless you want to do a complex integral you should ask that 0<x<1 instead of -1<x<1 as you currently have because say x=-1/2, then you have (-1/2)^(1/2) when t=1/2 | |
| Aug 13, 2018 at 0:42 | review | Suggested edits | |||
| S Aug 13, 2018 at 0:51 | |||||
| Aug 13, 2018 at 0:26 | history | edited | user3141592 | CC BY-SA 4.0 |
added 21 characters in body
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| Aug 13, 2018 at 0:16 | comment | added | imranfat | "which seems to be impossible"....right | |
| Aug 13, 2018 at 0:11 | history | asked | user3141592 | CC BY-SA 4.0 |