Timeline for Showing $\sqrt{2}\sqrt{3} $ is greater or less than $ \sqrt{2} + \sqrt{3} $ algebraically

10 events

when toggle format	what		by	license	comment
Mar 12, 2017 at 22:08	history	edited	Michael Lugo		edited tags
Dec 30, 2012 at 22:32	answer	added	Andy Brandi		timeline score: 6
Dec 4, 2012 at 2:15	history	edited	user4594	CC BY-SA 3.0	deleted 15 characters in body; edited title
Dec 2, 2012 at 7:01	history	tweeted			twitter.com/#!/StackMath/status/275132673410863105
Dec 2, 2012 at 5:17	answer	added	N. S.		timeline score: 17
Dec 2, 2012 at 4:43	review	First posts
Dec 2, 2012 at 4:45
Dec 2, 2012 at 4:42	vote	accept	Jeffrey L Whitledge
Dec 2, 2012 at 4:34	answer	added	user4594		timeline score: 41
Dec 2, 2012 at 4:30	comment	added	anon		Both quantities are positive so squaring preserves the inequality between them. Thus one checks if $2+2\sqrt{6}+3~\square~6$, which should be clear since $\sqrt{6}>1$.
Dec 2, 2012 at 4:25	history	asked	Jeffrey L Whitledge	CC BY-SA 3.0