Timeline for Showing $\sqrt{2}\sqrt{3} $ is greater or less than $ \sqrt{2} + \sqrt{3} $ algebraically
Current License: CC BY-SA 3.0
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Dec 30, 2012 at 23:17 | comment | added | Matt E | Dear Andy, This approach also has the advantage that we don't have to know in advance that the relationship is $>$, rather than $<$. Regards, | |
Dec 30, 2012 at 22:32 | history | answered | Andy Brandi | CC BY-SA 3.0 |