I am determining the Area-Product of the core required for a transformer to be used within a series resonant converter. The specifications are as follows:
- Switching frequency = 400 kHz
- Primary current = sine wave with a peak value of 500 mA
- Power output = 1 W
These are my calculations:
- I decided to use a core made out of N49 (since many such cores are already available)
- From the data given on this website, I have determined the saturation flux density of the ferrite core as: 0.04 T (approx.)
- The winding factor is considered to be 0.2
- Since we are dealing with 400 kHz, I decided to use a Litz wire with a 44 AWG strand size which has a bare Copper diameter of approximately 0.051 mm
- Since the RMS value of the primary current is 0.353 A, I decided to use a Litz wire with 18 such strands. This may be too much, but it is fine for my initial design (the overall conductor area now comes out to be 0.0368 \$mm^2\$).
- I calculated the current density of this conductor as follows: \$J = \frac{0.353}{0.0368} = 9.59 A/mm^2\$
- The Area-Product of the transformer is given by: \$A_cA_w = \frac{VI}{2\; f_{sw}\; B_m\; k_w\; J} \$ This gives a value of \$\frac{1}{2 \times 400000 \times 0.04 \times 10^{-6} \times 0.2 \times 9.59} \$ = \$ 16.293\; mm^4\$
Is my area-product calculation correct based on the specifications? Is the saturation flux density value as well as the current density, correct? Also, will there be any issue due to more number of strands (more than the required value) within the wire?