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After reading online, I have modeled this as an relation between the threshold voltage and the doping concentration:

For a N-channel MOSFET on a P-type substrate: $$ V_{T,N} \propto \sqrt{N_{A}} $$

For a P-channel MOSFET on a N-type substrate:

$$ V_{T,P} \propto - \sqrt{N_{D}} $$

which would then mean that an increase in substrate doping concentration leads to a higher magnitude threshold voltage (more positive for N-channel and more negative for P-channel).

How accurate is this? Does this qualitatively describe how the threshold voltage is affected by the semiconductor doping?

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  • \$\begingroup\$ Is there an operator (+ or -) missing from the top equation? \$\endgroup\$ Commented Oct 3, 2023 at 14:11
  • \$\begingroup\$ @TimWilliams No; nothing is missing. \$\endgroup\$
    – begin
    Commented Oct 3, 2023 at 14:22
  • \$\begingroup\$ Well, neither of them make any sense, what is alpha, why is voltage and cm^(-3/2) multiplied or subtr--- oooohhh, did you mean \propto instead of \alpha ? \$\endgroup\$ Commented Oct 3, 2023 at 14:33
  • \$\begingroup\$ Yes, that's the one! Aplogies! I'll edit the question. \$\endgroup\$
    – begin
    Commented Oct 3, 2023 at 15:42

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