I have a small control with a linear power supply, bridge rectifier, and smoothing capacitor. It turns on a motor for just 10 seconds or less and in the worst case only every 3 minutes, but maybe much longer.
When the motor is on, the ripple measured across the capacitor is around 600 mV or around 0.42 Vrms.
The capacitor is 1000 μF, 35 V. In the datasheet ESR is not shown but tan = 0.12 @ 120 Hz
So I used the calculation:
2 × 3.14 × 100 (100 Hz for me) × 0.001 = 0.628
then 0.12 / 0.628 = 0.191r
and then 0.42 / 0.191 ≈ 2.2 A
All the capacitors I have seen for this value appear to be in the same range 0.11-0.14.
This figure seems to be very high, but I am not basing that on anything, just surprised.
So the capacitor fitted has a ripple of 1945 mA at 100 kHz (derated by 80% for 120 Hz), I guess this is OK because of the low duty.
My question is:-
- Have I done the calculations correctly?
- If I have, am I using the correct method to select a capacitor, i.e. use the calculated ESR to arrive at the ripple current, then compare this with the ripple handling rating for that capacitor until one is found with the right combination. Interestingly, I found a couple of H-ripple capacitors, but they ended up with low ESR and therefore the current would be higher anyway.
I know the best answer would be to reduce the ripple voltage. But at the moment, I am just looking at an existing board and using it to understand what is going on.
at 100 kHz
thek
looks extraneous - ?) \$\endgroup\$