All Questions
5
questions
2
votes
0
answers
70
views
Ionic radius for tetrahedral metal–ligand complexes
The ionic radii for metal–ligand complexes that are in an octahedral coordination are easy to find. I understand that when the $\mathrm{e_g}$ orbital is filled, the ionic radius increases because the ...
- 748
4
votes
1
answer
2k
views
What's the configuration of chromium(III) in aqueous medium according to crystal field theory?
It has $\mathrm{3d^3}$ configuration, but how will we decide if they enter $\mathrm{t_{2g}}$ or $\mathrm{e_g}$ orbitals since we don't know which complex will form?
- 39
9
votes
2
answers
3k
views
In an octahedral complex, what happens to the electrons donated by the ligand?
I am trying to understand how complexes are coloured. After some reading, I found out this was due to the d-d splitting induced by the coordinate bonds of ligands to the central metal ion. The ...
- 181
9
votes
2
answers
5k
views
Why do copper (II) complexes contain so many valence electrons?
Consider tetraaminecopper (II) ion. $\ce{[Cu(NH3)4]^2+}$ or $\ce{[Cu(NH3)4(H2O)2]^2+}$.
The copper(II) ion has the electron configuration $\mathrm{[Ar]\ 3d^9}$. How do the 4 electron pairs from the ...
- 191
16
votes
1
answer
7k
views
Splitting of $d$ orbitals when ligands approach central metal ion
In my high school chemistry book, it is written that when ligands approach the central metal ion (transition metal ion) to form dative bonds, the $3d$ orbitals split into two: two which are in higher ...
- 2,423