Skip to main content

All Questions

5 votes
1 answer
73 views

What is less coordinating to metals? Triflates or hexafluorophosphates, and why?

I saw a reaction where $\ce{AgOTf}$ and $\ce{AgPF6}$ were used, but I am trying to discern the reactivity between the two silver salts. I read that triflates and hexafluorophosphates are both non-...
MrAmateurChem's user avatar
2 votes
0 answers
78 views

Does copper(II) hydroxide dissolve in ammonia solution?

According to University of Oregon — Chemistry Interactive Demonstrations and Educational Resources — Copper-Ammonia Complex, the equilibrium constant for the formation of copper(II) hydroxide is ...
Shira's user avatar
  • 620
5 votes
3 answers
279 views

Does chromium chromate — Cr₂(CrO₄)₃ — exist?

Is it possible to synthesise chromium(III) chromate/dichromate? The intended formulas are $\ce{Cr2(CrO4)3}$ and $\ce{Cr2(Cr2O7)3}$ and they feature both trivalent and hexavalent chromium. However, ...
user avatar
0 votes
1 answer
160 views

Amphoteric character of V2O5

In my NCERT textbook, in the chapter 'The d- and f-block elements', the last paragraph under oxides and oxoanions of metals goes like this: $(...)$ $\ce{V2O5}$ is, however, amphoteric though mainly ...
Harikrishnan M's user avatar
3 votes
2 answers
389 views

Why can't group 2B metals (Zn, Cd, Hg) form complexes with ligands such as CO, nitrosyl (NO), and olefins but do from complexes with NH3, CN- etc?

Why Group 2B metals (Zn, Cd, Hg) can form complexes with Ammonia ($\ce{NH3}$), Cyanide ($\ce{CN-}$) etc. and not with ligands such as carbonyl ($\ce{CO}$), nitrosyl ($\ce{NO}$), and olefins? What I ...
Bilal Malik's user avatar
0 votes
1 answer
109 views

D-d splitting in transition metal ions

Cu+2 ion has total of 9 electrons in its 3d orbital. When it undergoes d-d splitting an electronic transition can take place between t2 and e as in {Cu(CN)4}-2 complex because of the presence of one ...
Tabi Khan's user avatar
3 votes
0 answers
53 views

How to regenerate indium wires for vacuum seals?

I have a setup consisting in a vessel that eventually gets at low temperatures (approximately 85K - 87K) and needs indium wire as sealant. Unfortunately, we have to frequently open and close this ...
frappesco's user avatar
0 votes
0 answers
44 views

Why does the nitrito ligand have a higher Δo than water in the spectrochemical series?

I collected some data to determine the value of $\Delta_\text{o}$ for a some transition metal complexes (attached) and I'm very confused as to why $\Delta_\text{o}$ for the $\ce{ONO-}$ ligand is ...
ajk's user avatar
  • 49
2 votes
1 answer
193 views

Transition of electrons between t2g and eg to give colour of coordination compounds

In the case of a hexaaquairon (III) complex, the iron (III) ion has 5 electrons, each singly occupying one d orbital. As the d orbitals are occupied, the vacant 4s, 4p and 4d orbitals are hybridised ...
Tabi Khan's user avatar
1 vote
0 answers
171 views

Why exactly does copper have a higher melting point than zinc?

It is said that copper has a higher melting point than zinc because of the d electrons in copper being involved in metallic bonding. However, copper has no unpaired electrons in its d subshell just ...
wonderingwhy's user avatar
1 vote
0 answers
38 views

Can someone help with GAMESS input files for heavy atom calculations (MoS2, WS2, etc.)?

I'm doing computational research on transition metal dichalcogenides for my chemistry class and I want to calculate a transition state optimization for the reaction $\ce{MoS2 +N^- -> MoSN + S^-}$. ...
Daniel's user avatar
  • 11
0 votes
0 answers
29 views

What's the reason of curvature in Tanabe-Sugano diagrams?

Analysing Tanabe-Sugano diagrams it's evident that some of the lines are pretty parallels to that of the ground field whilst others are inclinated or have some curvature. I know what's the effect on ...
Chemistry.'s user avatar
0 votes
0 answers
41 views

Do the paired electrons of subshells' degenerate orbitals contribute to the total exchange energy?

For instance, in d7, there are 5 electrons with the same spin, and 2 electron with the opposite spin, meaning that there are only 3 unpaired electrons. So, which of these would be correct? (i) Total ...
Ayushi Kaushal's user avatar
-1 votes
1 answer
587 views

Why is iron(III) more stable than iron(II)?

What I have seen, and what has been answered before (Why Fe 3+ is more common than Fe 2+), is that it is due to the half filled d orbital of $\ce{Fe^3+}$ compared to $\ce{Fe^2+}$. I don't understand ...
Ariichu's user avatar
  • 21
1 vote
1 answer
210 views

Crystal Field Splitting for a d0 metal ion

Its well-known that crystal field splitting occurs because the electrons in d orbitals repel incoming ligands and the d orbitals are no longer degenerate. My question is now: is the repulsion (with ...
whitingsheep's user avatar

15 30 50 per page
1
2 3 4 5
18