Cu+2 ion has total of 9 electrons in its 3d orbital. When it undergoes d-d splitting an electronic transition can take place between t2 and e as in {Cu(CN)4}-2 complex because of the presence of one unpaired electron and it will contribute to its colour of the complex. Ti+3 has also only one unpaired electron in its d orbital so it can also undergo transition when d-d splitting occurs.
My question is that why would Ti+3 undergo d-d splitting in the first place when it has only one electron in only one of its degenerate d orbital. I mean d-d splitting occurs because of the repulsion between electrons of the approaching ligand and electrons in the d orbital and here only one of the d orbitals has one electron other degenerate d orbitals are empty so why would d-d splitting occur in the first place?? I will be very thankful if someone answers this.