Regex: delete all html tags from html tags, except some other html tags

Question

I need to delete all html tags, such as <p style="text-align: center;"> , but except </em> and </em> from the html tag <p class="glovo"></p>

EXAMPLE:

<p class="glovo">In these <p style="text-align: center;"> situations we may be forgetting to really <em>bend</em> at our practice and <em>sweat</em> at it.</p>

MUST BECOME:

<p class="glovo">In these situations we may be forgetting to really <em>bend</em> at our practice and <em>sweat</em> at it.</p>

I use this GENERIC formula:

REGION-START(?=(?:(?!REGION-FINAL).)*?FIND REGEX)(?=(?:(?!REGION-FINAL).)).+?REGION-FINAL\R?

REGION-START = <p class="glovo">
REGION-FINAL = </p>
FIND REGEX = <(?!/)[^>]*[^/]>(?!<em>|</em>)

So, my final regex becomes:

FIND:

<p class="glovo">(?=(?:(?!</p>).)*?<(?!/)[^>]*[^/]>(?!<em>|</em>))(?=(?:(?!</p>).)).+?</p>\R?

REPLACE BY: (LEAVE EMPTY)

The problem is that my regex selects THE ENTIRE html tag, not just the tags inside it. Can anyone help me?

Answer 1

• Ctrl+H
• Find what: (?:<p class="glovo">|\G).*?\K<(?!/?em>).*?>(?=.*</p>)
• Replace with: LEAVE EMPTY
• TICK Wrap around
• SELECT Regular expression
• Replace all

Explanation:

(?:                     # non capture group
    <p class="glovo">       # literally
  |                       # OR
    \G                      # restart from last match position
)                       # end group
.*?                     # 0 or more any character, not greedy
\K                      # forget all we have seen until this position
<                       # literally <
    (?!/?em>)               # not followed by em or /em
    .*?                     # 0 or more any character, not greedy
    >
(?=.*</p>)              # positive lookahead, make sure we have </p> somewhere after

Screenshot (before):

Screenshot (after):