No, this is unfortunately impossible.
The key here is that Hawking radiation bears no resemblance to the constituent matter that formed the black hole (this turns out to be a bit of a problem - see the black hole information paradox for more details). Black hole evaporation dramatically favors the production of lighter particles. For example, a black hole of temperature $T=100\;\text{GeV}\approx10^{15}\;\text{K}$ emits less than 3% of its emitted energy in the form of protons and antiprotons (see MacGibbon & Webber 1990). Over three quarters ends up as photons and neutrinos, with most of the remainder in the form of electrons and positrons.
As a rule of thumb, for a particle of mass $m$, a black hole needs to have a temperature $T$ such that its thermal energy $E_T\approx k_BT$ is on the order of $mc^2$ for that particle to be emitted significantly. Hence, hotter (read: less massive and closer to death) black holes may emit more massive particles, but the majority of their emission should still take the form of neutrinos and photons.
The upshot of all of this is that the mass of any object that travels inside the event horizon will reemerge in a form completely different from the original - dump a block of cheese into the black hole, and it won't emerge as anything like the original mixture of protons, neutrons and electrons, let alone a block of cheese.