15

I would to obtain a result similar to the image below. So far I only have \bigg( \Big( \big( a^q \big)^q \Big)^{\rotatebox{25}{$\cdots$}} \bigg)^q, without the brace.

I tried to follow this question, but there were no parenthesis and I was not able to circumvent this.

test

10
  • 1
    Hi, just a curiosity...for my opinion your question is good and I put +1. But do you have seen this image (I never I have seen this in a textbook)? :-)
    – Sebastiano
    Commented Feb 23, 2021 at 13:01
  • @Sebastiano : thanks for your encouraging comment. I did the image myself, but admittedly I never saw this in a book – maybe in the future if we get nice answers to my question ;-)
    – Watson
    Commented Feb 23, 2021 at 13:07
  • 1
    I don't even really know how to do it properly with a horizontal brace.
    – Watson
    Commented Feb 23, 2021 at 13:09
  • Yes, I'm agree fully with you....In this moment for me it is very complicated done it in math-mode. I think with TiKZ or PSTricks it is very simple. I have understood your thought. :-)
    – Sebastiano
    Commented Feb 23, 2021 at 13:09
  • 1
    @Sebastiano : a solution with TikZ (or PSTricks that I don't really know) would be fine. This is the approach used in the quesiton I linked.
    – Watson
    Commented Feb 23, 2021 at 13:10

3 Answers 3

15

Very easy with horizontal brace; somewhat less easy with rotated brace. I have no time right now to implement a general solution, so I'll go with a brute-force version for now.

\documentclass{article}

\usepackage{mathtools}% loads amsmath and graphicx

\begin{document}

\[
\biggl(\Bigl(\bigl(a
{% extra group for correct spacing
 \overbrace{
     {}^q \bigr)^q \Bigr)^{\rotatebox{20}{$\scriptstyle\dots$}} \biggr)^{\!\!q\mathstrut}
 }^{\text{$n$ times}}
}
\]

\[
\biggl(
\Bigl(
\bigl(a^q\bigr)^{q}
\Bigr)\quad
\biggr)^{
         \!\! q
         \setbox0=\hbox to 0pt{\hss
            \rotatebox{15}{$
              \overbrace{\kern1.8em\scriptstyle\mathstrut\dots\kern1.2em}^{\rotatebox{-15}{\scriptsize$n$ times}}
            $}%
         }%
         \lower1.5ex\box0
        }
\]

\end{document}

enter image description here

4
  • Thanks for your answer :-). In the horizontal case, it is possible to make the overbrace closer to the math formula? I tried to use \overbracket from mathtools but I am not able to get what I want. I tried to implement solutions from here, but negative depth does not seem to work anyway...
    – Watson
    Commented Feb 23, 2021 at 17:09
  • Probably using your idea with "\lower3ex\box0" can make it work, but I am not sure how.
    – Watson
    Commented Feb 23, 2021 at 17:13
  • @Watson No, you need no \lower in the first case. I've put an extra \mathstrut to increase the distance; you can simply remove that.
    – campa
    Commented Feb 23, 2021 at 19:38
  • Excellent works for every user! +1 for all.
    – Sebastiano
    Commented Feb 23, 2021 at 21:52
11

As given in my answer at Nested Mathematical Functions

The .4pt stacking gap added with each nesting will determine the growth rate of the parens.

\documentclass{article} 
\usepackage{scalerel,stackengine,graphicx,amsmath}
\stackMath
\ignoremathstyle
\newcommand\Comp[1]{\scaleleftright{(}{\addstackgap[.4pt]{#1}}{)}}
\newcommand\rdots{\ThisStyle{.\raisebox{.1ex}{$\scriptstyle.$}%
  \raisebox{.2ex}{$\scriptstyle.$}}}
\begin{document} 
\[ 
\stackinset{r}{1pt}{t}{-14.5pt}{\rotatebox{6}
  {$\overbrace{\rule{30pt}{0pt}}^{\textrm{\tiny$n$ times}}$}}{%
\Comp{\Comp{\Comp{a^q}^q}^{\rdots}}^q}
\] 
\end{document}

enter image description here

Here's a version where the stackgap is increased to .6pt, to bring out the increasing size of parens:

enter image description here

2
  • 1
    Thanks but you are missing the diagonal brace above the parenthesis, so this does not really address my question.
    – Watson
    Commented Feb 23, 2021 at 13:40
  • 1
    @Watson Please see my revision. Commented Feb 23, 2021 at 14:02
8

A solution with pstricks-add:

\documentclass{article}
\usepackage{pstricks-add}

\begin{document}

\[
\biggl(\Bigl(\bigl(a^{\pnode[0,1ex]{E}{q}}\bigr)^{\! \rnode{F}{\scriptstyle q}}\Bigr)\enspace \biggr)^{\!\!\rnode{G}{\scriptstyle q}\pnode[0,1ex]{H}}%
\psset{singleline, braceWidth=1.2pt, braceWidthInner=2pt, braceWidthOuter=2pt, nodesepB=-2pt}
\psbrace[rot=14,ref=c, linewidth=0.3pt](H)(E){\scriptstyle n\:\mathrm{times}}%
\ncline[linestyle=dotted, dotsep=2.pt, nodesepA=4.5pt, nodesepB=3.2pt]{F}{G}
\]

\end{document} 

enter image description here

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