How to convert code from test format to if fi format?

Question

I have code that opens a bash file in a terminal for entering the sudo password:

test "$IN_TERM" || {
    export IN_TERM=1
    konsole -e "$0"
    exit 0
} && true

I need to convert it to a form with if fi tags. I tried this option, but then an infinite number of terminals open:

if [[ -n $IN_TERM ]]; then  
    export IN_TERM=1  
    else  
    konsole -e "$0"  
    exit 0
fi

Thanks.

Answer 1

I think the most direct way to convert your code is:

if ! test "$IN_TERM"; then
    export IN_TERM=1
    konsole -e "$0"
    exit 0
fi

You can then rewrite it as

if ! [[ "$IN_TERM" ]]; then
    export IN_TERM=1
    konsole -e "$0"
    exit 0
fi

or

if [[ ! "$IN_TERM" ]]; then
    export IN_TERM=1
    konsole -e "$0"
    exit 0
fi

or

if [[ -z "$IN_TERM" ]]; then
    export IN_TERM=1
    konsole -e "$0"
    exit 0
fi