command line : Open exe file as if in another folder

Question

I'm trying to open an exe file located in

C:\someFolder

but since i'm doing it in cmd I do this

C:\ > someFolder\myExe.exe

But the problem is that inside someFolder are some files needed by the program

When I open it from another location, it opens in this particular location and can't access the files.

How should I do ?

EDIT :

I can't simply do CD first.

I want to call the exe in the context menu, so I have to add this command in a regristry KEY

Answer 1

Simply switch to the folder first:

cd /d C:\someFolder
myExe.exe

Answer 2

First you have to navigate to Somefolder.

Type in C:\>cd someFolder enter

Your prompt will look like this: C:\someFolder>

Now you can execute your program by typing myExe

Answer 3

Another method to run .exe file in command prompt

cmd /K “C:\SomeFolder\MyApp.exe”

Note: Don't forget to run command prompt with administrative privileges.

Answer 4

Changing the directory manually and then running the executable is fine for one off requirements. If you need to run this program multiple times consider adding a path variable. This lets you add the c:\somefolder to the path variable on your computer. Once that is added you can just type myExe.exe from the command prompt without adding the path to the file. Add a path variable by:

• Opening File Explorer
• Right-click on 'Your Computer' and select 'Properties'
• Select Advanced System Settings
• Click on 'Environment Variables'
• Scroll down the list of system variables and select 'Path'
• Click 'Edit'
• Add ;C:\somefolder (note the semicolon that ends the last path statement) and click 'OK'

You should now be able to run your executable from the command prompt