I have a column in my database called "dob" of type datetime. How do I select all the rows after a specific DoB in SQL Server 2005?
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2 Answers
Simply put:
SELECT *
FROM TABLE_NAME
WHERE
dob > '1/21/2012'
Where 1/21/2012 is the date and you want all data, including that date.
SELECT *
FROM TABLE_NAME
WHERE
dob BETWEEN '1/21/2012' AND '2/22/2012'
Use a between if you're selecting time between two dates
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4What rules apply with regard to the formatting of the date? I tested with "1/12/2012 13:14:33.000" and "1-12-2012 13:14:33.000" and both work.– BazCommented Mar 2, 2012 at 11:50
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1The example is misleading. 12 is not the month! It is the day and it is in american format. It is in this format: 'mm/dd/yyyy' example
SELECT * FROM TABLE_NAME WHERE dob > '1/13/2012. Now is clear that 13 is not month.– Daniel BCommented Sep 24, 2018 at 5:46 -
2@Daniel when in doubt, it is better to specify the conversion as in
WHERE dob >= Convert(datetime, '2019-12-15' )– helcodeCommented Dec 28, 2019 at 2:04 -
For MySQL, you can use
NOW()within your SQL statement, to get currentDateTime. For more details, please refer to: dev.mysql.com/doc/refman/8.0/en/date-and-time-functions.html– DainankCommented Jan 17 at 8:45
Let's say you want to get all records from a table called Table_One with a datetime column called date_value that have happened in the past six months...
CREATE TABLE (
date_value DATETIME
)
SELCECT *
FROM Table_One
WHERE date_value > DATEADD(month, -6, getdate());
This gives a bit more dynamic of a solution.
