I currently have some code that executes a task:
this.cmds = new String[] { "cmd.exe", "/c", customCmd };
ProcessBuilder pb = new ProcessBuilder(cmds);
try {
pb.start();
} catch (IOException e) {
e.printStackTrace();
}
This works perfectly and does what I expected.
However, I would like to actually display a visible cmd window when running this specific task.
Is this possible?
Thanks for your time,
Benna
Use this line:
this.cmds = new String[] { "cmd.exe", "/c", "start cmd.exe /k " + customCmd };
The first "cmd.exe", "/c" starts invisible window, but then inside you use command start cmd.exe /k ... to create visible window and it will stay open because of /k.
"start %ComSpec% /D /K " or "start %SystemRoot%\\System32\\cmd.exe /D /K " instead of "start cmd.exe /k " as in this case the first started cmd.exe does not need to search for the second to start cmd.exe file in file system and the second started cmd.exe does not read the AutoRun registry value. "/D" as additional argument (option) for first started cmd.exe before "/c" would be also useful to prevent reading the AutoRun registry value and executing it if really existing.
"cmd.exe" should be also replaced by System.getenv("ComSpec") for calling the Windows kernel library function CreateProcess with the executable to run with its fully qualified file name.
/kargument).