I'm experiencing this behavior in PyCharm Build #PY-222.4345.23 on macOS Monterey 12.6.1, which happens in both python 3.10 and 3.11.
def example(i):
match i % 4:
case 0:
if i > 10:
return 0
case 1:
if i > 10:
return 1
case 2:
if i > 10:
print(f'{i}, {i > 10}')
return 2
case 3:
if i > 10:
return 3
if __name__ == '__main__':
print(example(2))
In both python versions, debugger stops at 3rd return statement (unexpected, block should be unreachable) but doesn't actually return anything which is the expected behavior for the given input 2
python 3.11 (1 breakpoint to reproduce)
python 3.10 (2 breakpoints to reproduce)
If switch and cases were replaced with if/elif blocks, the very same breakpoint is never reached which is exactly the behavior I'm expecting for the switch blocks.
def example(i):
j = i % 4
if j == 0:
if i > 10:
return 0
elif j == 1:
if i > 10:
return 1
elif j == 2:
if i > 10:
print(f'{i}, {i > 10}')
return 2
elif j == 3:
if i > 10:
return 3
if __name__ == '__main__':
print(example(2))
return 2. If you continue (e.g. line by line), the debugger will execute thereturnand so you will have the2. But on your code,return 2should never be executed. You callreturn 2only ifi > 10, but you havei = 2, so no return. Please specify better what do you expect and what you get.i = 2.example(14)and not forexample(2)