Capture group in specific string

Question

I have a string:

User{self=https:example.com, name=S1234, displayName=Johny B, accountId=null, [email protected], active=true}'

I try to capture group and get Johny B in sed. I have proper regex: displayName=(.*?),

but below sed command return me all string:

's/.*displayName=\(.*?\),/\1/'

Does this answer your question? Non greedy (reluctant) regex matching in sed? — Wiktor Stribiżew, Commented Sep 3, 2021 at 9:13
ok, when I change to 's/.*displayName=\([^/]*\),/\1/' I get substring starting ofJohny B to the end of string — Kucharsky, Commented Sep 3, 2021 at 9:25
You have a comma to exclude, 's/.*displayName=\([^,]*\),/\1/', not a slash. — Wiktor Stribiżew, Commented Sep 3, 2021 at 9:28

sseLtaH · Accepted Answer · 2021-09-03 09:31:38Z

1

You can try this sed

sed -E 's/.*displayName=([^,]*).*/\1/' $file

You have further strings after the match which you need to account for.

answered Sep 3, 2021 at 9:31

sseLtaH

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