Recall all arguments from a previously executed command in bash shell

Question

This link gives the pointer on how to recall the arguments of the last successfully executed command in the command line.

I wanted to access all the arguments of a particular command from the shell history.

To me only this syntax works

ls f1 f2 f3
file !ls:1-3 --> file f1 f2 f3

And, if I use !* which should give all the arguments of previous command throws error

file !ls:!*
-bash: !: unrecognized history modifier

I can only use this syntax (i.e) all arguments of last executed command.

file !*

Problem with the above methods are if I had executed ls with some option, for eg: ls -l, then the file command would have thrown a different output as the option of ls would be considered as first argument in this case.

Answer 1

Try leaving out the second !:

$ ls foo bar baz
foo bar baz
$ echo !ls:*
echo foo bar baz
foo bar baz

Answer 2

!ls returns the last ls command. If you want the second to last or even an older ls execution you can use history to retrieve the command you want

history | grep ls

355  ls foo bar baz
446  ls -a
447  ls -ah

And then use @Jon solution or yours to get the arguemnts

echo !355:*