Replace array entry with spread syntax in one line of code? [duplicate]

Question

I'm replacing an item in a react state array by using the ... spread syntax. This works:

let newImages = [...this.state.images]
newImages[4] = updatedImage
this.setState({images:newImages})

Would it be possible to do this in one line of code? Something like this? (this doesn't work obviously...)

this.setState({images: [...this.state.images, [4]:updatedImage})

Answer 1

use Array.slice

this.setState({
  images: [
    ...this.state.images.slice(0, 4),
    updatedImage,
    ...this.state.images.slice(5),
  ],
});

Edit from original post: changed the 3 o a 4 in the second parameter of the slice method since the second parameter points to the member of the array that is beyond the last one kept, it now correctly answers the original question.

Answer 2

Once the change array by copy proposal is widely supported (it's at Stage 3, so should be finding its way into JavaScript engines), you'll be able to do this with the new with method:

// Using a Stage 3 proposal, not widely supported yet as of Nov 17 2022
this.setState({images: this.state.images.with(4, updatedImage)});

Until then, Object.assign does the job:

this.setState({images: Object.assign([], this.state.images, {4: updatedImage}));

...but involves a temporary object (the one at the end). Still, just the one temp object... If you do this with slice and spreading out arrays, it involve several more temporary objects (the two arrays from slice, the iterators for them, the result objects created by calling the iterator's next function [inside the ... handle], etc.).

It works because normal JS arrays aren't really arrays¹ (this is subject to optimization, of course), they're objects with some special features. Their "indexes" are actually property names meeting certain criteria². So there, we're spreading out this.state.images into a new array, passing that into Object.assign as the target, and giving Object.assign an object with a property named "4" (yes, it ends up being a string but we're allowed to write it as a number) with the value we want to update.

Live Example:

const a = [0, 1, 2, 3, 4, 5, 6, 7];
const b = Object.assign([], a, {4: "four"});
console.log(b);

If the 4 can be variable, that's fine, you can use a computed property name (new in ES2015):

let n = 4;
this.setState({images: Object.assign([], this.state.images, {[n]: updatedImage}));

Note the [] around n.

Live Example:

const a = [0, 1, 2, 3, 4, 5, 6, 7];
const index = 4;
const b = Object.assign([], a, {[index]: "four"});
console.log(b);

---

¹ Disclosure: That's a post on my anemic little blog.

² It's the second paragraph after the bullet list:

An integer index is a String-valued property key that is a canonical numeric String (see 7.1.16) and whose numeric value is either +0 or a positive integer ≤ 2⁵³-1. An array index is an integer index whose numeric value i is in the range +0 ≤ i < 2³²-1.

So that Object.assign does the same thing as your create-the-array-then-update-index-4.

Answer 3

You can use map:

const newImages = this.state.images
  .map((image, index) => index === 4 ? updatedImage : image)

Answer 4

You can convert the array to objects (the ...array1), replace the item (the [1]:"seven"), then convert it back to an array (Object.values) :

array1 = ["one", "two", "three"];
array2 = Object.values({...array1, [1]:"seven"});
console.log(array1);
console.log(array2);

Answer 5

Here is my self explaning non-one-liner

 const wantedIndex = 4;
 const oldArray = state.posts; // example

 const updated = {
     ...oldArray[wantedIndex], 
     read: !oldArray[wantedIndex].read // attributes to change...
 } 

 const before = oldArray.slice(0, wantedIndex); 
 const after = oldArray.slice(wantedIndex + 1);

 const menu = [
     ...before,  
     updated,
     ...after
 ]

Answer 6

I refer to @Bardia Rastin solution, and I found that the solution has a mistake at the index value (it replaces item at index 3 but not 4).

If you want to replace the item which has index value, index, the answer should be

this.setState({images: [...this.state.images.slice(0, index), updatedImage, ...this.state.images.slice(index + 1)]})

this.state.images.slice(0, index) is a new array has items start from 0 to index - 1 (index is not included)

this.state.images.slice(index) is a new array has items starts from index and afterwards.

To correctly replace item at index 4, answer should be:

this.setState({images: [...this.state.images.slice(0, 4), updatedImage, ...this.state.images.slice(5)]})

Answer 7

first find the index, here I use the image document id docId as illustration:

const index = images.findIndex((prevPhoto)=>prevPhoto.docId === docId)
this.setState({images: [...this.state.images.slice(0,index), updatedImage, ...this.state.images.slice(index+1)]})

Answer 8

I have tried a lot of using the spread operator. I think when you use splice() it changes the main array. So the solution I discovered is to clone the array in new variables and then split it using the spread operator. The example I used.

var cart = [];

function addItem(item) {
    let name = item.name;
    let price = item.price;
    let count = item.count;
    let id = item.id;

    cart.push({
        id,
        name,
        price,
        count,
    });

    return;
}

function removeItem(id) {
    let itemExist = false;
    let index = 0;
    for (let j = 0; j < cart.length; j++) {
        if (cart[j].id === id) { itemExist = true; break; }
        index++;
    }
    if (itemExist) {
        cart.splice(index, 1);
    }
    return;
}

function changeCount(id, newCount) {
    let itemExist = false;
    let index = 0;
    for (let j = 0; j < cart.length; j++) {
        console.log("J: ", j)
        if (cart[j].id === id) {
            itemExist = true;
            index = j;
            break;
        }
    }
    console.log(index);
    if (itemExist) {
        let temp1 = [...cart];
        let temp2 = [...cart];
        let temp3 = [...cart];
        cart = [...temp1.splice(0, index),
            {
                ...temp2[index],
                count: newCount
            },
            ...temp3.splice(index + 1, cart.length)
        ];
    }

    return;
}

addItem({
    id: 1,
    name: "item 1",
    price: 10,
    count: 1
});
addItem({
    id: 2,
    name: "item 2",
    price: 11,
    count: 1
});
addItem({
    id: 3,
    name: "item 3",
    price: 12,
    count: 2
});
addItem({
    id: 4,
    name: "item 4",
    price: 13,
    count: 2
});

changeCount(4, 5);
console.log("AFTER CHANGE!");
console.log(cart);