how to remove a suffix of a string after a character in bash?

Question

I have a string like this.

30: sometext 57: sometext ....

I want to iterate over the numbers that come before the colon inside a shell script.

Answer 1

With egrep - Vertical Output

echo "30: sometext 57: sometext" | egrep -o '[0-9][0-9]'
30
57

With awk - Horizontal Output

echo "30: sometext 57: sometext"|awk -F'["|:| ]' '{print $1, $(NF-2)}'
30 57