Is there no XOR operator for booleans in golang?
I was trying to do something like b1^b2 but it said it wasn't defined for booleans.
asked Apr 12, 2014 at 3:22
Add a comment
|
3 Answers
There is not. Go does not provide a logical exclusive-OR operator (i.e. XOR over booleans) and the bitwise XOR operator applies only to integers.
However, an exclusive-OR can be rewritten in terms of other logical operators. When re-evaluation of the expressions (X and Y) is ignored,
X xor Y -> (X || Y) && !(X && Y)
Or, more trivially as Jsor pointed out,
X xor Y <-> X != Y
answered Apr 12, 2014 at 3:26
-
17
-
87
-
3@Jsor Doh. I miss the obvious far too often :| Updated. Commented Apr 12, 2014 at 4:27
-
22You could say that Go does have an exclusive-or operator for
bool, and it's spelled!=. Commented Apr 12, 2014 at 5:41 -
3all good until you need something like
boolVar XOR boolFunc()Commented Jul 2, 2019 at 6:07
With booleans an xor is simply:
if boolA != boolB {
}
In this context not equal to performs the same function as xor: the statement can only be true if one of the booleans is true and one is false.
-
-
5@Adonis it works. XOR returns true if an only if only 1 of the 2 operands are true, and in your expression there are always a true and a false results, and
false != trueis true, which is the same asfalse XOR true– phuclvCommented Apr 13, 2022 at 8:07
Go support bitwise operators as of today. In case someone came here looking for the answer.
