You can check if all the fields of the node are null:
Node firstNode = list.firstNode;
if(firstNode.data == null &&
firstNode.nextPointer == null &&
firstNode.previousPointer == null) {
//Do stuff
}
Or to prevent code repetition, you can either create an instance method isNull() to do the test or create a NULL object and override the equals method in your Node class to check if a node is equal to the null node as you described.
class Node<E> {
//The null node, assuming your constructor takes all three values.
public static final Node NULL = new Node(null, null, null);
//Fields here with constructors etc.
@Override
public void equals(Object obj) {
if(!obj instanceof Node) return false;
Node<?> node = (Node<?>)obj;
if(node.data.equals(this.data) &&
node.nextPointer == this.nextPointer &&
node.previousPointer == this.previousPointer) {
return true;
} else {
return false;
}
}
Then when you want to check if a node is null you can do:
if(list.firstNode.equals(Node.NULL)) {
//Do stuff
}
list.firstNode
is not equal tonull
?