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Is there a better way of checking if a word exists in an array of strings without including Punctuation Marks?

what I have tried,

const sArray=['Lorem','Ipsum','typesetting-','industry.','Ipsum?','has' ]


console.log(sArray.toString().replaceAll(".","").includes("industry")) //true

console.log(sArray.includes("industry")) //false
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    sArray.some(e => e.includes("industry")). Pay attention to the fact that the includes here is String.prototype.includes, not Array.prototype.includes.
    – Gerardo Furtado
    Commented Oct 10, 2022 at 10:25
  • As @GerardoFurtado said or, in case you need to manipulate the string when it is present, you can use Array.prototype.find() (const foundItem = sArray.find(e => e.includes("industry")); if (foundItem !== -1) { /* manipulate the string */ })
    – secan
    Commented Oct 10, 2022 at 10:40

2 Answers 2

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Something like this?

sArray.some(str => str.includes('industry'))
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If you do a lot of operations on the array, I suggest creating a new reference of the array after replacing, then dealing with the new array.

const sArray=['Lorem','Ipsum','typesetting-','industry.','Ipsum?','has' ]

const trasformedArray = sArray.map(i => i.replaceAll('.', ''));

console.log(trasformedArray.includes("industry"))

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