list subdirectories recursively

Question

I want to write a shell script so as to recursively list all different subdirectories which contain NEW subdirectory (NEW is a fixed name).

Dir1/Subdir1/Subsub1/NEW/1.jpg
Dir1/Subdir1/Subsub1/NEW/2.jpg
Dir1/Subdir1/Subsub2/NEW/3.jpg
Dir1/Subdir1/Subsub2/NEW/4.jpg
Dir1/Subdir2/Subsub3/NEW/5.jpg
Dir1/Subdir2/Subsub4/NEW/6.jpg

I want to get

Dir1/Subdir1/Subsub1
Dir1/Subdir1/Subsub2
Dir1/Subdir2/Subsub3 
Dir1/Subdir2/Subsub4

How can I do that?

Answer 1

find . -type d -name NEW | sed 's|/NEW$||'

--- EDIT ---

for your comment, sed does not have a -print0. There are various ways of doing this (most of which are wrong). One possible solution would be:

find . -type d -name NEW -print0 | \
  while IFS= read -rd '' subdirNew; do \
          subdir=$(sed 's|/NEW$||' <<< "$subdirNew"); \
          echo "$subdir"; \
  done

which should be tolerant of spaces and newlines in the filename

Answer 2

ls -R will list things recursively.

of find . | grep "/NEW/" should give you the type of list you are looking for.

Answer 3

You could try this:

find . -type d -name "NEW" -exec dirname {} \;