I saw many examples, but for some reason it still does not work for me.
This is the command I'm executing:
NUMBER=$(docker logs vault | grep Token)
NUMBER=${NUMBER##*": "}
NUMBER=$(echo $NUMBER | sed 's/^token=(.*)$//g')
echo $NUMBER
I want to get the value after '=', which is a string basically. I tried using GREP, and other regex's but I either get nothing, or just the original string.
Please advise.
To get text after a delimiter better to use cut instead of sed as in this example:
echo 'token=dsa32e3' | cut -d= -f2
dsa32e3
-d= sets delimiter as = for cut-f1 makes cut print first field
With sed you can simply remove the token=, with
NUMBER=$(echo token=dsa32e3 | sed 's/^token=//g')
echo $NUMBER
Other non-regexp based alternatives are possible, as other users pointed out.
Another fun possibility is using the negative lookbehind, not supported by sed, so I used perl.
NUMBER=$(echo token=dsa32e3 | perl -pe 's/.*(?<=token=)([a-z0-9]*)/$1/g')
echo $NUMBER
()capture groups with Basic Regular Expressions, where they have to be\(\)(or use ERE instead,sed -E/sed -r) and b) you're removing the complete line, but you want to re-insert the captured group again.cuthereecho 'token=dsa32e3' | cut -d= -f2number=$(echo token=dsa32e3);number=${number#*=}