Remove all text after the last instance of a string in Unix

Question

So let's say I have a file that contains the following text:

string1
string1
string2
string1
string2
string1
string1

And I wanted to get rid of all text after the last occurrence of "string2". For example the output would look like this:

string1
string1
string2
string1
string2

What's an easy way to do this in bash?

Answer 1

tac file | awk '!f && /string2/ { f=1 }; f' | tac

tac prints the file upside down. awk sets a flag on first occurence of the pattern string2 (which is the last occurence in the original version) and prints a line only if the flag is set.

Answer 2

grep approach:

grep -zo '.*string2' yourfile && echo

The output:

string1
string1
string2
string1
string2

---

-z - treat input and output data as sequences of lines, each terminated by a zero byte (the ASCII NUL character) instead of a newline

---

To write the result into a file do the following action:

(grep -zo '.*string2' yourfile && echo "")  > output.txt

Answer 3

Well, here's a simple grep :

grep -B100000000 string2 yourfile

Just make that number bigger than the number of lines in your file.