0

i have a ajax post from my form. when it succeed, i want to redirect to another web page..

What i have now:

$.ajax({
        type : 'POST',
        url : '/system/login.php',
        data : formData,
        dataType : 'json',

    success: function(data) {
        if(!data.success){
            if(data.errors.username){
                alert(data.errors.username);
            }

            if(data.errors.password){
                alert(data.errors.password);
            }
            if(data.errors.login){
                alert(data.errors.login);
            }
        }
        else{
            location.href = "http://localhost/me.php"
        }
    },
    error: function(xhr){
     alert(xhr.responseText);
  }
});

Is there someone who can help me? because nothing i tried works.

2
  • See specifically this comment on the DUP answer
    – RiggsFolly
    Commented May 11, 2017 at 12:20
  • Does it trigger the error function? Because the system/login.php probably doesnt return a 200 OK Commented May 11, 2017 at 12:21

2 Answers 2

1

change this line

location.href = "http://localhost/me.php"

to

window.location.href='http://localhost/me.php'

make sure ajax response is ok

0

jQuery is not necessary, and window.location.replace(...) will best simulate an HTTP redirect.

window.location.replace(...) is better than using window.location.href, because replace() does not keep the originating page in the session history, meaning the user won't get stuck in a never-ending back-button fiasco.

If you want to simulate someone clicking on a link, use location.href

If you want to simulate an HTTP redirect, use location.replace

For example:

// similar behavior as an HTTP redirect
window.location.replace("http://localhost/me.php");

// similar behavior as clicking on a link
window.location.href = "http://localhost/me.php";

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