Send input files data with ajax [duplicate]

Question

html markup:

<input id="fileSelect" type="file" id="file" name="files[]" multiple="multiple" accept="image/*" />

I am uploading multiples files with php. I want to make an array of upload files and send to server with ajax. how to make an array of the multiple selected files?

JavaScript:

jQuery.ajax({
    url: 'insertfiles.php',
    type: "POST",
    data: {
      file: // array of selected files.
    },
    success: function(data){
    },
    error: function(data){
      alert( 'Sorry.' );
    }
});

Answer 1

Use the code below.

var formData = new FormData($("#formid")[0]);
jQuery.ajax({
  url: 'insertfiles.php',
  type: "POST",
  data: formData,
  success: function(data) {
        
  },
  error: function(data) {
    alert( 'Sorry.' );
  },
  cache: false,
  contentType: false,
  processData: false,
});

Hope this helps you

Answer 2

Modern browsers that support the HTML5 file stuff have in the <input> element a "files" property. That will give you a file list reference, which has a length property.

As the property is already an array so you just need to access it or iterate through it.

JS

var input = document.getElementById('id');
console.log(input.files);

for (var i = 0; i < input.files.length; i++) {
 console.log(input.files[i]);
}

Answer 3

var formData = new FormData(this);
debugger;
$.ajax({
  url: formURL,
  type: 'POST',
  data: formData,
  mimeType: "multipart/form-data",
  contentType: false,
  cache: false,
  processData: false,
  success: function (data, textStatus, jqXHR) {
    debugger;
  },
  error: function (jqXHR, textStatus, errorThrown) {
                    
  }
});

The above code will help you post content plus files in one submit call.

The post method parameter should include HttpPostedFileBase[] file so the list of files will appear in this file parameter

Answer 4

This is my code for multiple file upload. Please refer this

$fileCount = count($_FILES);
for($i=0; $i < $fileCount; $i++) {
$fileName = (!empty($_FILES["file-$i"]["name"])) ? $_FILES["file-$i"]["name"] : '';

$hostName = "REDACTED";
$userName = "REDACTED";
$passWord = "REDACTED";
$dbName   = "b7_15386696_db_printer";

$query    = "INSERT INTO print_table (NAME, EMAIL, PHONE, ADDRESS, FILENAME, NUMBEROFCOPY, SREQUIREMENTS, FIELD1)
VALUES ('$name', '$emailId', '$phone', '$address', '$fileName', '$ncopy', '$requirements', CONVERT_TZ(NOW(),'+00:00','+09:30'))";

$connect = mysqli_connect($hostName,"$userName","$passWord","$dbName");
// Check connection
if (mysqli_connect_errno()) {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
}