I have a lua table that contains 2 key pieces of data. I would like to sort the table in ascending order by the "num1" column, or if thats not possible, they by the key value in ascending order
Here's what I have so far:
local widgets = {}
widgets[1568] = {}
widgets[1568]["num1"] = 99999
widgets[1568]["val2"] = "NA"
widgets[246] = {}
widgets[246]["num1"] = 90885
widgets[246]["val2"] = "NA"
widgets[250] = {}
widgets[250]["num1"] = 95689
widgets[250]["val2"] = "NA"
widgets[251] = {}
widgets[251]["num1"] = 95326
widgets[251]["val2"] = "NA"
widgets[252] = {}
widgets[252]["num1"] = 95301
widgets[252]["val2"] = "NA"
widgets[256] = {}
widgets[256]["num1"] = 95303
widgets[256]["val2"] = "NA"
-- ATTEMPT TO SORT
--table.sort(widgets, function(a,b) return tonumber(a.num1.value) < tonumber(b.num1.value) end)
--table.sort(widgets, function(a,b) return tonumber(a.num1) < tonumber(b.num1) end)
--TRY SORTING BY ID:
table.sort(widgets, function(a,b) return tonumber(a) < tonumber(b) end)
for i, v in pairs(widgets) do
print(v.num1)
end
Any suggestions would be appreciated. Right now, I'm reviewing Sort a Table[] in Lua to try to understand the "spairs" function. But that example is slightly different because I have a table within a table...
Thanks.
SOLUTION
In line with the answer below, I created a new table and added the records from the old table, one by one, using table insert like so:
local new_widgets = {}
for i, v in pairs(widgets) do
table.insert(new_widgets, id=v.id, num1= v.num1, num2 = v.num2)
end
then I sorted new_wigets.
table.sort
for this, since the indices in your table do not start at 1 and run consecutively. internally, table.sort runs from 1 to #table, so it is not iterating the widgets. you'll have to roll your own sorting function and call it yourself. see the lua docs about table.sort to verify. your function will have to iterate the table withpairs
.