Obtaining value out of a script with bash

Question

I have a file with many lines, with lines such as so:

PHP_VERSION="5.3.12"
NPM_VERSION="1.10"

From a linux command line, how would I take out just the version number? For this example, how would I get an output like 5.3.12 if for say I wanted the PHP version out of the given input file.

Answer 1

Your trying to get it with bash?

. /path/to/file
echo $PHP_VERSION

?

Answer 2

I would use something like:

var="$(grep -F -m 1 '$variable =' file)"; var="${var#*\'}"; var="${var%\'*}"

Reference: BASH shell use regex to get value from file into a parameter