How to correct determine ReflectionMethod::getPrototype

Question

Completely unclear how to determine whether a method has a prototype or not.

Example:

<?php
class MyClass
{
    public function foo()
    {
    }
}

$refl = new ReflectionClass('MyClass');

var_dump($refl->getMethod('foo')->getPrototype());

Output for PHP 5.1.2 - 5.5.5:

Fatal error: Uncaught exception 'ReflectionException' with message 'Method MyClass::foo does not have a prototype'...

I would like to implement something like bool ReflectionMethod::hasPrototype( void ) for my ReflectionMethod wrapper.

Any ideas?

Answer 1

getPrototype is documented to throw if a prototype does not exist, so it's straightforward to convert that to a boolean:

public function hasPrototype()
{
    try {
        $this->getPrototype();
        return true;
    }
    catch (\ReflectionException $e) {
        return false;
    }
}