How may I detect the name of the directory (or better yet the entire path) in which my shell script is run?
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For Bash, see: Getting the source directory of a Bash script from within.– kenorbCommented Jul 19, 2017 at 18:39
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4 Answers
what shell? What operating system?
For starters try
man pwd
$PWD
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And if you do want just the directory's name, instead of the full path, read man basename too.– Roger PateCommented Nov 30, 2009 at 2:46
This, I believe, is the most portable way:
dir=$(cd -P -- "$(dirname -- "$0")" && pwd -P)
answered Nov 30, 2009 at 14:06
This is not as trivial as it looks like. Check out this question and this
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The question is about determining the script execution directory, but your answer is for determining the name / directory of the script file. Commented Mar 12, 2017 at 19:44
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Could you add a little bit more information? See meta.stackexchange.com/questions/8231/…– MarcoCommented May 5, 2018 at 23:02
alternative method
pid=$$
path=$(ps -eo pid,args| awk -vp=$pid '$1~p{print $3}')
case "$path" in
./* ) pwd;;
* ) echo $path;;
esac
answered Nov 30, 2009 at 3:11
