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May
21
comment I know $o(f) + o(g) = o(\max(f, g))$. What about $o_\text{P}(f) + o(g)$?
@RobertIsrael Thank you, I'll make this change!
May
21
comment I know $o(f) + o(g) = o(\max(f, g))$. What about $o_\text{P}(f) + o(g)$?
@GregMartin yep, you are correct! Thank you for this comment!
May
21
comment I know $o(f) + o(g) = o(\max(f, g))$. What about $o_\text{P}(f) + o(g)$?
@GregMartin I think this is true! Right now, I'm tempted to believe $\mathbb{E}\left[o_\text{P}(f)\right] = o(f)$, and thus $o_\text{P}(f) + o(g) = o_\text{P}(f) + \mathbb{E}\left[o_\text{P}(g)\right] = \mathbb{E}\left[o_\text{P}(f) + o_\text{P}(g)\right] = o(\max{(f,g)})$, but I need to formally prove or disprove this
May
21
revised I know $o(f) + o(g) = o(\max(f, g))$. What about $o_\text{P}(f) + o(g)$?
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May
21
revised I know $o(f) + o(g) = o(\max(f, g))$. What about $o_\text{P}(f) + o(g)$?
added 125 characters in body
May
21
comment I know $o(f) + o(g) = o(\max(f, g))$. What about $o_\text{P}(f) + o(g)$?
@Thomas Andrews Realized I forgot to define $o_\text{P}$, it's convergence in probability. Post edited
May
21
revised I know $o(f) + o(g) = o(\max(f, g))$. What about $o_\text{P}(f) + o(g)$?
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May
20
asked I know $o(f) + o(g) = o(\max(f, g))$. What about $o_\text{P}(f) + o(g)$?
2023
Nov
4
awarded Supporter
Nov
4
comment Using Comparison Operators Between Datasets and Vectors in R: What am I doing wrong?
Ahh that makes sense. Man I was wracking my brain trying to understand what was happening! Thank you so much!
Nov
4
accepted Using Comparison Operators Between Datasets and Vectors in R: What am I doing wrong?
Nov
4
comment Using Comparison Operators Between Datasets and Vectors in R: What am I doing wrong?
Ah, that makes sense! What comparisons was R doing?
Nov
4
asked Using Comparison Operators Between Datasets and Vectors in R: What am I doing wrong?
Jul
24
comment Is non-nominal confidence interval coverage normal in practice?
@Henry The standard error of my estimator is indeed small, but I'm worried that reviewers will focus more on the coverage failure.
Jul
24
accepted Is non-nominal confidence interval coverage normal in practice?
Jul
24
comment Is non-nominal confidence interval coverage normal in practice?
Thank you for your reply. I guess I always assumed that, as long as you have a larger sample size, the mean estimator should be sufficiently normal, and thus skewed data would still produce nominal coverage. I'm embarrassed to not have known that there were normality assumptions, lol!
Jul
24
revised Is non-nominal confidence interval coverage normal in practice?
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Jul
24
comment Is non-nominal confidence interval coverage normal in practice?
@callculus42 Sample size is 500, but I also observed 100 and 300.
Jul
24
asked Is non-nominal confidence interval coverage normal in practice?
Jul
8
comment GLMs vs Time Series analyses
@stweb Not really. It's one sample that just happens to have a time-related variable.
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