An entry in Fortnightly Topic Challenge #32: Grid Deduction Hybrids
Puzzlers, I am presenting a set of six duo-grids! Of course, I need to tell you how they work - you are given a grid. Looking at it, you are given the two puzzle types embedded in it and the operation. You are also given the values for some of the squares. Because some of the puzzles were... difficult to make, I have modified some rules to existing puzzles. In retrospect, this is pretty much the same as my Adderlink puzzle (see there for an example). Ultimately, the goal is to deduce the two sub-puzzles in each puzzle. So, for example, if I had a 5 in a square and the operation is addition, then I know that I have to have either: 0 and 5, 4 and 1, 3 and 2, etc. in the puzzles (if you still don't understand, just click the adderlink above, the rules are the same except that the puzzles and operations change).
Grid 1: Slitherlink $+$ Sudoku (i.e latin square)
Grid 2: Kakuro $\div$ Skyscraper
Grey squares mean that nothing goes there for the Kakuro ONLY, and also the Kakuro has the additional property that no two squares are the same horizontally, vertically or diagonally including through the center square.
$\color{red}{\text{user39583 proved that this puzzle's ambiguous; see his solution for the intended sol.}}$ (don't forget to +1 his solution!)
Grid 3: Kenken ($+\times \div -$ ^) Haisu
Oh, how careless of me! I forgot to put the regions in. Well, I'll tell you this, the Kenken and Haisu have the same regions. The (large) number appearing in the cell is Kenken and ANY of the operations on the Haisu. So, like, a 1 could be a 6 in the Kenken and a 5 in the Haisu (6-5) or it could be a 1 in the Kenken and anything in the Haisu (1^anything = 1) etc. Same applies for the little numbers, except that the little numbers in the Kenken are again, any operation: $+\times \div -$ ^. So, for example, if the numbers in the Kenken region were 3 and 4, and the little number in the Haisu was, say 10, then the little number in the final grid could be: 22 ($3\times 4+10$) (12 is a valid Kenken clue), 17 ($3+4+10$) (7 is a valid Kenken clue) but not 43 ($3+4\times 10$) (no combination of a valid Kenken clue and Haisu 10 exist).
$\color{red}{\text{user39583 has pointed out that the bottom left 50 should really be a 40}}$
Lastly, the Kenken has numbers 1-6: at most one of any number in a row or column
The Haisu was used with permission from TGE
Grid 4: Nachbarn $\times$ Nawabari
Well, they were the names I found on here (Don't worry, there are English explanations). Two things: The Nachbarn regions do not necessarily have to be the same size. And also, although every black number has to be in its own region, the grey one does not.
Grid 5: Fillomino $+$ Ripple effect
Ripple effect regions are fillomino regions.
Grid 6: ??? $\square$ ???
Weird, huh? I forgot everything about this puzzle - the sub-puzzles used, operations, everything. Well, actually, I did remember something - that these sub-puzzles are different from everything above. Also the operations used ($+\times \div -$ ^) form a latin square - so for example, if the top left number was formed by addition, then no other number in the first row or column was formed by addition.
I'm extremely sorry about the gross underestimation of difficulty in this and the inconvenience therecaused. Sorry to all attempters who attacked the earlier version without this picture.
Any queries or comments, feel free to ask below. I will answer any question about how the puzzles work
Hint helpfulness level 0
There is almost a 1-1 bijection between squares and letters
Hint helpfulness level 1
There is also a hint in the fluffle of text at the beginning
Hint helpfulness level 1 (again)
The puzzles come in pairs; the extraction also deals with them in pairs
Hint helpfulness level 2
Each square corresponds to a letter, much like in a polybius cipher. Then you need to do some anagramming