From the number of points, we can deduce that Atleticolino (A) won two games and drew one, Barcelino (B) won one, drew one, and lost one, and Diminuto (D) drew one game and lost three. Chicorrotico (C) could have one win and two losses, or three draws. However, the total number of draws must be even, so C drew all three games.
Now we know that C drew against A, B, and D, so A won against B and D, and B won against D.
If A won against B, then B must have conceded at least one goal. Then A must also have conceded at least one goal. If A conceded a goal while winning two games and drawing one, then A must have scored at least three goals, so C must have scored at least six goals.
In the games that C played, C's opponents scored the same number of goals as C. There must have been at least one goal scored in each of the other three games. Therefore C could not have scored eight or more goals, or else there would be at least 19 total goals. So C scored exactly six goals, and A scored exactly three.
For A to score exactly three goals, they must have conceded exactly one goal, and won against B and D by a margin of exactly one goal. There are three cases, all of which produce a solution:
- A conceded a goal to B. Then A went 2-1 against B, 0-0 against C, and 1-0 against D. B has conceded two goals to A, so they conceded no goals to C or D: B went 0-0 against C and 1-0 against D. Then C went 6-6 against D, with a total of 17 goals scored.
A 2-1 B
A 0-0 C
A 1-0 D
B 0-0 C
B 1-0 D
C 6-6 D
- A conceded a goal to C. Then A went 1-0 against B, 1-1 against C, and 1-0 against D. B conceded one goal to D (couldn't be to C, because it would be impossible to have a 0-0 draw). So B went 0-0 against C and 2-1 against D. C went 5-5 against D, with a total of 17 goals scored.
A 1-0 B
A 1-1 C
A 1-0 D
B 0-0 C
B 2-1 D
C 5-5 D
- A conceded a goal to D. Then A went 1-0 against B, 0-0 against C, and 2-1 against D. B conceded another goal against C (couldn't be to D, because there would end up being too many goals scored). So B went 1-1 against C and 1-0 against D. C went 5-5 against D, again with a total of 17 goals.
A 1-0 B
A 0-0 C
A 2-1 D
B 1-1 C
B 1-0 D
C 5-5 D