$$\det\frac{\partial(x,y)}{\partial(r,\varphi)}\\ \sum_{n=2}^\infty \ddot{\frac{t^n}{n!}} $$
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2 Answers
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Follow up to rand al'thor answer
The graph shows:
sec(x)
By combining the 2 other answers, we obtain:
sec + r + et = $secret$
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Graph:
work in progress...
$\det\frac{\partial(x,y)}{\partial(r,\varphi)}=r$, because
$x,y$ are Cartesian coordinates and $r,\varphi$ are polar coordinates, in the 2-dimensional plane.
$\sum_{n=3}^\infty \ddot{\frac{t^n}{n!}}=e^t$, because
differentiate $t^n$ twice to get $n(n-1)t^{n-2}$, so the sum is $\sum_{n=3}^\infty \ddot{\frac{t^{n-2}}{(n-2)!}} = \sum_{n=1}^\infty \ddot{\frac{t^n}{n!}}=e^t$.
answered Jun 17, 2015 at 10:28
sec(x-2.2)and I couldn't figure out why it was important. I wish you had donesec(x)instead =\ ... +1 anyway for creativity $\endgroup$