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    – bobble
    Commented Jun 30 at 14:11

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I believe the answer is D.

A green cross without the boxes tangent on it(in each row 1 cross has no boxes on it and the other one has) and 2 pairs of yellow boxes because in first row we have 4 pairs, in 2nd row we have 6 so now it must be different( with D we have 5 pairs). Same goes with columns. 4 in 1st column, 6 in 2nd and 5 in the 3rd.

Furthermore, in each row, regarding the squares with the crosses, we have 1 pair in left box and 1 pair in the right one, in the second we have 2 on the left and 2 on the right, so in the third we must have 1 pair in one of them and 2 on the other so that we have all 3 different combinations (1-1, 2-2 and 1-2 or 2-1)

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