Lukas wants to draw our attention to …
… the PSE Advent Calendar.
The completed sequence is:
103, 91, 79, 0, 119, 61, 28, 79, 21, 15, 0, 78, 119, 14, 79, 21, 61, 119, 5
The matches represent …
… the numbers from 0 to 127 in binary form. Each 1×2 “box” has seven possible positions for matches. These positions are bits in a binary representation of a seven-bit number. Bit 0 is the centre match, bits 1 through 6 are anticlockwise starting from the top left upright match.
These numbers are arranged in a straightforward fashion: Row-wise starting from 0 in the top left corner to 127 in the bottom right corner. The boxes overlap, so that a match on the border could be a bit that’s set on either of the neighbours or on both.
-- 6 --
| | (1 << 0) == 1
1 5 (1 << 1) == 2
| | (1 << 2) == 4
-- 0 -- (1 << 3) == 8
| | (1 << 4) == 16
2 4 (1 << 5) == 32
| | (1 << 6) == 64
-- 3 --
And the sequence?
The seven-match boxes are, of course, seven-segment displays in disguise. You can assemble the bits of the numbers or look up the index in the match pattern. (But be careful with overlapping matches.) The numbers read:
103 91 79 0 x x 28 x x x 0 78 x x x x x x 5
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _
|_| |_ |_ |_| |_| |_| |_| |_| | |_| |_| |_| |_| |_| |_| _
| _| |_ |_| |_| |_| |_| |_| |_| |_ |_| |_| |_| |_| |_| |_| |
The missing matches …
… had been identified by Lypyrhythm based on the regular pattern of the binary boxes. Now that we know what the boxes are, we can verify that finding.
Eleven machsticks are missing and eleven numbers in the sequence are missing. If we look at the missing matches, we can see that they all belong to letter shapes. (There are some minor ambiguities: The stem of the d could belong to a U and the stem of the A could be part of an N. These disambiguities are resolved by the fact that u/v and n are already represented unambiguously by lower-case seven-stick symbols.)
Below are the letters drawn out, i.e. no longer overlapped, and with the missing sticks highlighted with ugly DOS-blocks. (Sorry for that.)
_ | |_ _ | |_ _ | |_ _ | ▐_
| | | | _ _ _ _ |_ |_ ▐_ |_
_ | |_ ▄ | |_ _ | |_ _ | |_
| | | || |▐ || || | _| _| _| _||_||_||_||_|
| _|| ||_| | _|| ||_| | _|| ||_| | _|| ||_|
| | | | _ _ _ _ |_ |_ |_ |_
| _|| ||_| | _|| ||_| | _|| ||_| | ▄▌| ||_|
| | | || || || || | _| _| _| _||_||_||_||_|
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
_ | |_ _ | |_ _ | |_ _ | ▐▄
| | | | _ _ _ _ |_ |_ |_ |_
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
_ | |_ _ | |_ _ | |_ _ | |_
| | | || || || || | _| _| _| _||_||_||_||_|
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
| _|| ||_| | _|| ||_| | _|| ||_| | _|| ||_|
| | | | _ _ _ _ |_ |_ |_ |_
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
| _|| ||_| | _|| |▐▄| | _|| ||_| | _|| ||_|
| | | || || || || ▌ _| _| _| _||_||_||_||_|
We can fill in the blanks:
The x's are:
3 × A 2 × E 2 × d 2 × n 1 × L 1 × t
and we get:
103 91 79 0 119 61 28 79 21 15 0 78 119 14 79 21 61 119 5
_ _ _ _ _ _ _ _ _
|_| |_ |_ |_| _| |_ _ |_ | |_| | |_ _ _| |_| _
| _| |_ | | |_| |_| |_ | | |_ |_ | | |_ |_ | | |_| | | |