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A mirrored game is a game where black makes the same moves as white. Doing this, find the fastest possible checkmates for:

  • A Regular Rook

  • A Promoted Rook

  • A Regular Bishop

  • A Promoted Bishop

  • A Regular Knight

  • A Promoted Knight

  • A Promoted Queen

  • A Pawn

May you have fun finding out the answers!

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    $\begingroup$ This seems way too chess and less puzzle to me. $\endgroup$
    – Prince North Læraðr
    Commented Apr 8, 2019 at 19:43
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    $\begingroup$ What do you mean copy0cat questions? Also, just because it'll get shelled in CSE doesn't mean it belongs here either. $\endgroup$
    – Prince North Læraðr
    Commented Apr 8, 2019 at 19:46
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    $\begingroup$ @North What does that even mean? Being chessy doesn't make something not a puzzle ... $\endgroup$
    – Rand al'Thor
    Commented Apr 8, 2019 at 20:28
  • $\begingroup$ Does every move have to be mirrored prior checkmate? Also, is the mirroring a literal reflection. Does the rook on h1 correspond to that on h8 (or a8)? $\endgroup$
    – hexomino
    Commented Apr 8, 2019 at 22:02

2 Answers 2

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There was this question on a competitive programming contest. It asked how to checkmate by any pieces (including King!) but not all for promoted one. You may see the full solution here:

Problem L - IPSC 2018

And here they are:

Queen

1. d4 d5 2. Qd3 Qd6 3. Qh3 Qh6 4. Qxc8#
Link (online viewer)

Knight

1. Nc3 Nc6 2. Ne4 Ne5 3. e3 e6 4. Ne2 Ne7 5. c3 c6 6. Nd6#
Link (online viewer)

Rook

1. Nf3 Nf6 2. Ng5 Ng4 3. Nxh7 Nxh2 4. Nxf8 Nxf1 5. Ne6 Ne3 6. Rxh8#
Link (online viewer)

Promoted Rook (and Promoted Queen)

1. c4 c5 2. d4 d5 3. dxc5 dxc4 4. c6 c3 5. c7 c2 6. cxd8=R#
Link (online viewer)

Pawn

1. f4 f5 2. g4 g5 3. gxf5 gxf4 4. Nf3 Nf6 5. Ng5 Ng4 6. f6 f3 7. f7#
Link (online viewer)

Bishop

1. e4 e5 2. f4 f5 3. exf5 exf4 4. f6 f3 5. fxg7 fxg2 6. Be2 Be7 7. Bh5#
Link (online viewer)

King

1. f3 f6 2. Kf2 Kf7 3. Kg3 Kg6 4. Kh3 Kh6 5. e3 e6 6. Bd3 Bd6 7. Bg6 Bg3 8. hxg3 hxg6 9. Kg4#
Link (online viewer)

Promoted Bishop (my own answer -- may not be optimal)

1. g4 g5 2. h4 h5 3. hxg5 hxg4 4. g6 g3 5. g7 g2 6. Nh3 Nh6 7. Ng5 Ng4 8. g8=B g1=B 9. Bxf7#
Link (online viewer)

Promoted Knight (my own answer -- may not be optimal)

1. c4 c5 2. b4 b5 3. cxb5 cxb4 4. b6 b3 5. b7 b2 6. bxc8=N bxc1=N 7. e3 e6 8. Ne2 Ne7 9. Nd6#
Link (online viewer)

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  • $\begingroup$ @RewanDemontay I've just updated for promoted rook/queen, but not yet for the others >< $\endgroup$
    – athin
    Commented Apr 9, 2019 at 1:51
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    $\begingroup$ @RewanDemontay added the rests, you may check them ^^ $\endgroup$
    – athin
    Commented Apr 9, 2019 at 2:40
  • $\begingroup$ Nice one! And eh.. is promoted king a thing in chess.. lol $\endgroup$
    – athin
    Commented Apr 9, 2019 at 4:15
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Partial Answer

A Regular Rook

1. h4, h5
2. g3, g6
3. Bh3, Bh6
4. Bg4, Bg5
5. hxg5, hxg4
6. Nf3, Nf6
7. Nd4, Nd5
8. Rxh8#

Optimal, clarified by OP.

A Promoted Rook/Promoted Queen

1. h4, h5
2. g4, g5
3. hxg5, hxg4
4. g6, g3
5. Bh3, Bh6
6. Be6, Be3
7. Nf3, Nf6
8. Nd4, Nd5
9. g7, g2
10. gxh8R# for the Rook case.

or

10. gxh8Q# for the Queen case

Not optimal.

A Regular Bishop

1. g3, g6
2. Nf3, Nf6
3. Ng5, Ng4
4. Nc3, Nc6
5. Nd5, Nd4
6. Nf4, Nf5
7. Nxg6, Nxg3
8. Bg2, Bg7
9. Bd5, Bd4
10. Bxf7#

Not optimal.

A Regular Knight

1. e3, e6
2. Ne2, Ne7
3. g3, g6
4. Nbc3, Nbc6
5. Ne4, Ne5
6. Nf6#

Optimal, clarified by OP.

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  • $\begingroup$ I've got a different finishing position. Both knights move. The g-knight only moves in 2 while all other moves are performed with the b-knights. Therefore, you should have knights in front of the kings. $\endgroup$
    – hexomino
    Commented Apr 8, 2019 at 23:57
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    $\begingroup$ Here: apronus.com/chess/pgnviewer/… $\endgroup$
    – hexomino
    Commented Apr 9, 2019 at 0:13
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    $\begingroup$ Move 4 should be Nbc3, not Nec3, I'll edit to clarify. $\endgroup$
    – hexomino
    Commented Apr 9, 2019 at 0:14
  • $\begingroup$ The regular rook is not optimal, can check my answer for this. $\endgroup$
    – athin
    Commented Apr 9, 2019 at 1:30
  • $\begingroup$ @athin Ah okay, just the knight one then, it seems. $\endgroup$
    – hexomino
    Commented Apr 9, 2019 at 8:39

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