A regular D20 die (icosahedron) as depicted above has the number 1 to 20 arranged on its faces such that the sum of opposing faces is 21. Each triangular face touches three other faces directly by a shared edge, f.e. (1)-{7,13,19}.
Find an optimum series of face-to-face tilts with the following rules:
- You may start with any chosen face shown (i.e. facing upwards)
- You may show the same face more than once during the series.
- The complete series should have shown each number at least once
- The sequence of numbers needs to contain the ascending order of the numbers 1 to 20.
Of course there are many such sequences, so the condition to optimize is the following:
- Each tilt move which lowers the shown number from what it was before counts as a negative point.
- Minimize the amount of negative points.
What is the sequence of tilts with the lowest score?
Some clarifications
I do believe that "regular" D20 dice have identical numbering, but I might be wrong. Therefore the die used for this puzzle is the one depicted above.
This would be a valid tilting sequence of the D20 from above (face-by-face):
19,1,13,5,15,12,2,20,14,6,9,19,3,19,9...
This would be a valid number sequence:
14,11,1,5,8,2,1,7,6,3,4,5,6,12,11,7,8,1,2,9,10,11,12,13,14,7,18,15,16,17,18,19,3,20
( This sequence can not be gotten by tilting the D20 face-by-face, though!! )
The score for the sequence above would be:
14,11,1,5,8,2,1,7,6,3,4,5,6,12,11,7,8,1,2,9,10,11,12,13,14,7,18,15,16,17,18,19,3,20
= 12 negative points