Notation: a number 'XY' denotes the blob in the Xth row and the Yth column, and the grid uses x's for crewmates, o's for impostors, dashes for unidentified, and @ for pairs where at least one is a crewmate. Word info is given as "_____ [known letters being filled in] (<yellow letters>) no: <excluded letters>". Hopefully this makes sense!
Step 1: Identifying Inconsistencies
One of 14 and 61 must be incorrect. Therefore, there is no r in the word.
One of 23 and 33 must be incorrect. Therefore, there is no i in the word.
One of 12 and 52 must be incorrect. Therefore, there is an e in the word.
One of 25 and 64 must be incorrect. Therefore, at least one of these conditions is true: there is a v in the 1st place and/or an s in the 3rd.
This gives us this grid with the following letters/word knowledge:
--x--
-x@--
-x---
-----
--x--
@---x
_____ (e) no: ir
Step 2: First Assumption
Assuming 12 and 14 are both correct, 52 and 61 must both be incorrect. Therefore, the letters {eto} are in the word and there is an s in the 3rd position. This means that 33 is incorrect, implying there is an f in first position. This means we have the word info "f_st_ (oe)". The final word then must be "foste", or else the first row doesn't have an incorrect clue. This isn't a word, so either 12 or 14 is incorrect, as is either 52 or 61. We do learn, however, that there is no c, and e is not in the 5th position.
x-x-x
-x@x-
-x---
-----
--x--
@---x
_____ (e) no: cir
Step 3: A More Useful Assumption
Assuming 23 is correct implies that s is in the 3rd place, f is in the 1st, and o is in word, but not in the 4th place. This means that 25 is incorrect, which implies there is no d in the word. Since we now "know" 4/5 of the letters [f_s__ (oe)], one coloured clue in row 4 is wrong. The full set of letters becomes {fsonel}, which means both 52 and 55 must be incorrect. This is impossible, so 23 is incorrect, which implies there is no d or o in the word.
x-x-x
xxoxx
-x---
-----
--x--
----x
_____ (e) no: cdior
Step 4: Cleaning Up
Since there's no o, 54 is incorrect, meaning that v is in the first position and there is no a or p. Since v is in first position, 31 is incorrect, implying that there is no h or y, but there is an s in the word (but not in the 3rd place). Since v is in first position, 14 is incorrect, and e is not in the 5th position.
xxxox
xxoxx
oxxxx
-----
--x--
xxxox
v____ (es) no: ahikpqry [only one e]
Step 5: Too Many Letters
Any black clue being incorrect would lead to too many letters, therefore they're all correct. Since we have three letters already {ves}, the remaining two rows provide {nlut} (the e included in the letters we already have) - this means the two "e" clues are correct and the e is in the 2nd place.
xxxox
xxoxx
oxxxx
x-xx-
x-xx-
xxxox
ve___ (s) no: ahikpqry
Step 6: Finishing Off with Assumptions
Assuming the l clue is correct, we have the word info 've--l (nsu) no: ahiprty'. Therefore, the possible "words" including s (but not in the 3rd position) are 'vensl' and 'veusl', which aren't real. Therefore, the l clue is incorrect.
Assuming the u clue is correct, possible words meeting our criteria are 'vensu', 'venus', 'veuns', and 'veusn'. 'Venus' is close but is a proper noun; therefore, the u clue is incorrect.
xxxox
xxoxx
oxxxx
xxxxo
xoxxx
xxxox
ve___ (nstu) no: ahiklpqry
Final Answer:
Omitting the non-words 'venst', 'vetns', and 'vetsn', we are left with 'VENTS', a perfect word for six sussy impostors! 😳😳😳