1
vote
Current through points with no voltage drop
That's an ammeter, not a voltmeter, and "there's no voltage drop" just suggests
the ideal-ammeter characteristic of zero resistance, as the
correct approximation to apply.
There can, of ...
- 9,943
1
vote
Accepted
A capacitor partially filled with dielectric
For some background, let's remind ourselves that the electric field is a conservative field. Because of this, we can define potentials that are independent of the particular path of integration. So ...
- 2,697
1
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Electric field at a point due to dielectric inserted in between a parallel plate capacitor
The induced charges on the dielectric will attract the charges on the plates. Since the dielectric is inserted partially between the two plates, the charge on the plate near the dielectric will ...
- 513
1
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Electric field at a point due to dielectric inserted in between a parallel plate capacitor
Consider the situation before the dielectric was introduced (left diagram) and after the dielectric was introduced (right diagram).
There are two possible scenarios.
The first is when the capacitor ...
- 97.9k
1
vote
How will the capacitance of a capacitor reduce when the distance between the plates is increased?
Now I know that if the potential difference between the plates increase that capacitance will reduce
Ideally, this is not the case. Capacitance depends on the geometry of the conductors, not the ...
- 57.2k
1
vote
Accepted
How can I deduce a capacitance of a capacitor without existing formulaes?
Since you are assuming $k$ is a constant, you can take it outside of your integral formula to give
$V(t) = k \int_0^t r \space dt$
But $\int_0^t r \space dt$ is the charge $Q(t)$ that has accumulated ...
- 56.4k
1
vote
Working of batteries and supply of charges through them when connected to capacitors
You: is there any new charge coming out of the battery?
Ans: No new charge can't come out. The total charge of the whole system will be constant (conservation of charge). Simply you can think some ...
- 11
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Working of batteries and supply of charges through them when connected to capacitors
Note that the net charge on the combination of both plates is +60 Coulombs both before and after being connected to the battery. So the battery has not "supplied" any charge. It has just “...
- 73.7k
1
vote
Cannot catch a minus sign mistake when deriving the ODE for an LC circuit
You're using opposite sign conventions for the potential differences across the capacitor and the inductor.
Arbitrarily designate one terminal of the capacitor as $C_{in}$ and the other one as $C_{out}...
- 1,255
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