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0 votes
2 answers
67 views

Voltage: work to move a charge, or difference of electric potential?

Let's say I have a single positive charge inside of an electrostatic field. I want to move this charge from point A to point B and determine the voltage between the two points. Points A and B are the ...
oh no's user avatar
  • 3
0 votes
3 answers
169 views

Why is Power in an electric circuit equal to $VI$? [closed]

Where did this formula come from? Everyone I asked just told me to substitute values of in ohms law to derive this but no one told why is power equal to voltage * current. Part of the reason for this ...
potato's user avatar
  • 9
2 votes
5 answers
611 views

Can we use work equation to derive Ohm's law?

Ohm's law states: $$\textbf V=\textbf I\cdot\text R$$ where $\textbf V$ is voltage, the electric potential difference from a point to another (Electric potential is the potential energy of a positive ...
user7777777's user avatar
1 vote
2 answers
117 views

Working of battery in circuit

The battery has a potential difference. So, shouldn't battery generate an electric field directing from the positive side to the negative side? If that's the case, we know that potential in a wire(...
madness's user avatar
  • 1,179
0 votes
3 answers
512 views

What is the correct derivation of energy stored in parallel plates capacitor?

I am little confuse in deriving the energy stored in the capacitor. I read two different derivation in totally different way but yet getting the same value. Here they have calculated work done by ...
Md Faiyaz's user avatar
  • 121
2 votes
1 answer
2k views

Energy of a Continuous Charge Distribution

I had a question regarding the derivation for the following expression of the energy of a continuous charge distribution $$W=\frac{\epsilon_0}{2}\int_\text{all space} E^2d\tau$$ To get this result, we ...
JS30's user avatar
  • 129
9 votes
10 answers
6k views

Why is Power = Voltage $\times$ Current?

So P = I*V because V is the amount of energy per coulomb and I is the amount of electrons going past a cross sectional area in one second. So if we do the math, since V = J/C and I = C/sec, if we ...
ikigai20's user avatar
  • 191
2 votes
2 answers
516 views

What is the meaning of external work in electric potential?

We learned that $$-Work = \Delta U = q(Va-Vb).$$ However, we write that $$W = q(Va-Vb)$$ in this question. Why don't we write the minus sign in the equation? How does external work affect the minus ...
llee7 jkonn's user avatar
0 votes
1 answer
32 views

How do we know that a battery has 5 voltage?

Since Voltage = work done per coulomb and in a battery we don't know how much coulomb exists (or is it known because I read somewhere that we are unaware) and for the work done I assume we can find it ...
25 Simran Tiwari's user avatar
-1 votes
1 answer
236 views

Decrease of potential by negative charge

Initially there is a body $A$. To increase it's potential we give positive charge to it which means we need to do more work to bring a test charge from infinity. Now we bring a negatively charged body ...
madness's user avatar
  • 1,179
0 votes
1 answer
3k views

Derivation of the electric potential inside a non-conducting sphere

Assuming that the electric field at a distance $r$ from the center of a non-conducting sphere with radius $R$ and uniformly distributed charge $Q$ is $E=\frac{1}{4\pi\epsilon_0}\frac{Q}{R^3}r$, we are ...
KarmaPenny's user avatar
1 vote
0 answers
22 views

Can work be positive when looking at a negative charge experiencing a voltage? [closed]

Using V=W/q when q is negative and V is positive do we write the work as negative? In my question it says “How much work is done in moving 6 electrons through a potential difference of 2V?” My answer ...
LAMAR__44's user avatar
-1 votes
1 answer
241 views

How is the work done along an equipotential line zero?

If a charge is brought from some distance to a point which lies on the equatorial line of an electric dipole, the work done is 0 and so is the electric potential. But how should I imagine this?
Samyak Marathe's user avatar
3 votes
2 answers
194 views

Deriving $-\vec{\nabla}V$ from $V_b-V_a=-\int\vec{E}\cdot d\vec{l}$

I'm trying to understand how to derive $-\vec{\nabla}V$ from $V_b-V_a=-\int\vec{E}\cdot d\vec{l}$. I'm not really familiar with the gradient operator, I know how to compute it and I know that $\vec{\...
Andrea Burgio's user avatar
1 vote
2 answers
371 views

How can an electric field do work? What does the work in this case?

I'm studying electromagnetism and I'm a little confused on what this textbook says: The highlighted part is what makes me confused. First thing, "The difference in potential energy is equal to ...
Andrea Burgio's user avatar

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