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In QCD, Why the order parameter of chiral symmetry takes the form $\langle0 \lvert \bar{\psi}\psi\rvert 0 \rangle$?
A simple question, why the order parameter of QCD chiral symmetry (chiral condensate) take this form:
(or let's say why choose $\bar{\psi}\psi$ to judge there is SSB(spontaneous symmetry breaking) or ...
