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-1 votes
2 answers
116 views

How Fast Must a Man Run to See Rain Falling horizontally?

The fact that tan 90° is undefined indicates a key issue in the problem. Does this mean it is impossible to observe rain falling at 90 degree? When rain is observed to be falling at 90° with the y-...
Dron Bhattacharya's user avatar
-2 votes
1 answer
61 views

The distance problem [closed]

Say a car has to move from Point A to Point B on the surface of the earth. The car starts from rest at Point A at time $t=0s$ reaches point B at time $t=10s$ with a constant velocity of $1000 m/s$. ...
Jeffy James's user avatar
0 votes
1 answer
121 views

Velocity of Separation and Relative Velocity

I have some problems in understanding a concept, which has been used in the problem in the picture: I don't understand what are we actually using to solve this question. Are we using relative ...
Samyak Sambuddha's user avatar
4 votes
5 answers
711 views

Can't understand a statement about motion

From the book where I am studying motion, It says Motion is a combined property of the object under study and the observer. There is no meaning of rest or motion without the viewer. I know that, for ...
Daniel Joseph's user avatar
5 votes
5 answers
1k views

How is a change in KE the same in every inertial reference frame?

This is not about special relativity, so assume speeds are much less than $c$. This article says a change in kinetic energy (KE) remains constant in all inertial reference frames. So the kinetic ...
across's user avatar
  • 410
0 votes
1 answer
48 views

Kinetic energy consistency

Suppose a vehicle 1 is on the top of another vehicle 2 (we can think of it like a big platform). Imagine the following independent experiments: Suppose that the top vehicle accelerates to a speed $...
Maximus's user avatar
  • 31
0 votes
3 answers
239 views

A question about relative motion and how to make sense of it

So, here is the question: Assuming the 2D Cartesian system and the basis vectors $\hat{i}$ and $\hat{j}$, we have two cars A and B located at (0,6) and (-30,0) respectively. Car A starts moving with a ...
Floatoss's user avatar
  • 169
4 votes
3 answers
1k views

Kinetic energy "paradox" -- where am I wrong here? [duplicate]

Body $A$ is at rest and has mass $2$, so the energy required in order to accelerate it to a speed of $v$ is $v^2$, and so the energy required in order to accelerate it to a speed of $2$ is $4$. On the ...
Snaw's user avatar
  • 143
0 votes
1 answer
107 views

CoM-and-relative velocity

In our scrip we are considering the elastic collision between two particles, one with inital velocity $\vec v$ and the other $\vec w$. We also consider that the particles have the same mass. ...
imbAF's user avatar
  • 1,398
1 vote
1 answer
124 views

Velocity of an object with respect to the same object

I know that velocity of an object with respect to the same object is a null vector but I'm not able to get a grasp of it. Whatever I had thought till now is that if I'm sitting in a train (which may ...
Lalit Tolani's user avatar
2 votes
2 answers
131 views

Can I apply Newton's equations of motion to relative motion?

We know that Velocity of A relative to B is $$ \vec v_{A|B} = \vec v_A - \vec v_B $$ and Acceleration of A relative to B is $$ \vec a_{A|B} = \vec a_A - \vec a_B $$ So, is it correct to do this to ...
anonymous's user avatar
  • 227
0 votes
2 answers
296 views

Why is relative motion at constant velocity the same as being at rest?

If I am a passenger who plays catching-the-ball game inside a vehicle that moves with a constant velocity in a straight road, why can I catch the ball repeatedly that as if the vehicle is at rest? How ...
user avatar
1 vote
4 answers
138 views

Motion between two particles in a relative manner

Suppose a particle A is travelling in east direction with velocity of x m/s and another particle B is travelling with velocity y m/s in the west direction. Why does the the particle B appears to move ...
Atharav Karhad's user avatar
0 votes
1 answer
117 views

Relative motion between two particles

I already know the relation of relative velocity as : Vab=Va-Vb So is there any derivation for this relation or is just how it is defined? Relating to this i am finding some hard time to imagine why ...
Atharav Karhad's user avatar
1 vote
3 answers
250 views

Defining what it means for a reference frame to move with a velocity $\mathbf{u}$ with respect to another

In describing a Galilean transformation, for example, one might say that if a reference frame $S'$ is moving at a velocity $\mathbf{u}$ with respect to $S$, then an object traveling at a velocity $\...
user avatar

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